-5-6(10x+3)=3/2(2x-2)+3

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Solution for -5-6(10x+3)=3/2(2x-2)+3 equation: 



-5-6(10x+3)=3/2(2x-2)+3

We move all terms to the left:

-5-6(10x+3)-(3/2(2x-2)+3)=0



Domain of the equation: 2(2x-2)+3)!=0

x∈R



We multiply parentheses

-60x-(3/2(2x-2)+3)-18-5=0

We multiply all the terms by the denominator


-60x*2(2x-2)-18*2(2x-2)+3)-5*2(2x+3)-(3-2)+3)=0

We add all the numbers together, and all the variables

-60x*2(2x-2)-18*2(2x-2)+3)-5*2(2x+3)-1+3)=0

We add all the numbers together, and all the variables

-60x*2(2x-2)-18*2(2x-2)+3)-5*2(2x=0

Wy multiply elements

-120x^2(2-36x(2+3)-5*2(2x=0

We add all the numbers together, and all the variables

-120x^2(2-36x5-5*2(2x=0

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