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-5/(2s)-1s=10
We move all terms to the left:
-5/(2s)-1s-(10)=0
Domain of the equation: 2s!=0We add all the numbers together, and all the variables
s!=0/2
s!=0
s∈R
-1s-5/2s-10=0
We multiply all the terms by the denominator
-1s*2s-10*2s-5=0
Wy multiply elements
-2s^2-20s-5=0
a = -2; b = -20; c = -5;
Δ = b2-4ac
Δ = -202-4·(-2)·(-5)
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-6\sqrt{10}}{2*-2}=\frac{20-6\sqrt{10}}{-4} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+6\sqrt{10}}{2*-2}=\frac{20+6\sqrt{10}}{-4} $
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