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-5/2(x)=x+2
We move all terms to the left:
-5/2(x)-(x+2)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-5/2x-x-2=0
We multiply all the terms by the denominator
-x*2x-2*2x-5=0
Wy multiply elements
-2x^2-4x-5=0
a = -2; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·(-2)·(-5)
Δ = -24
Delta is less than zero, so there is no solution for the equation
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