-5/2x-10+2=8/x-5

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Solution for -5/2x-10+2=8/x-5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(-5/2)*x-10+2 = 8/x-5 // - 8/x-5

(-5/2)*x-(8/x)-10+2+5 = 0

(-5/2)*x-8*x^-1-10+2+5 = 0

-5/2*x^1-8*x^-1-3*x^0 = 0

(-5/2*x^2-3*x^1-8*x^0)/(x^1) = 0 // * x^2

x^1*(-5/2*x^2-3*x^1-8*x^0) = 0

x^1

(-5/2)*x^2-3*x-8 = 0

(-5/2)*x^2-3*x-8 = 0

DELTA = (-3)^2-(-8*4*(-5/2))

DELTA = -71

DELTA < 0

x in { } 

x belongs to the empty set

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