-5/3b+4=5-3/5b

Solution for -5/3b+4=5-3/5b equation:

-5/3b+4=5-3/5b

We move all terms to the left:

-5/3b+4-(5-3/5b)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

-5/3b-(-3/5b+5)+4=0

We get rid of parentheses

-5/3b+3/5b-5+4=0

We calculate fractions


(-25b)/15b^2+9b/15b^2-5+4=0

We add all the numbers together, and all the variables

(-25b)/15b^2+9b/15b^2-1=0

We multiply all the terms by the denominator


(-25b)+9b-1*15b^2=0

We add all the numbers together, and all the variables

9b+(-25b)-1*15b^2=0

Wy multiply elements

-15b^2+9b+(-25b)=0

We get rid of parentheses

-15b^2+9b-25b=0

We add all the numbers together, and all the variables

-15b^2-16b=0

a = -15; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-15)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-15}=\frac{0}{-30}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-15}=\frac{32}{-30}
=-1+1/15
$