-5/3y=7+4y

Solution for -5/3y=7+4y equation:

-5/3y=7+4y

We move all terms to the left:

-5/3y-(7+4y)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We add all the numbers together, and all the variables

-5/3y-(4y+7)=0

We get rid of parentheses

-5/3y-4y-7=0

We multiply all the terms by the denominator


-4y*3y-7*3y-5=0

Wy multiply elements

-12y^2-21y-5=0

a = -12; b = -21; c = -5;
Δ = b2-4ac
Δ = -212-4·(-12)·(-5)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{201}}{2*-12}=\frac{21-\sqrt{201}}{-24}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{201}}{2*-12}=\frac{21+\sqrt{201}}{-24}
$