-5/4c-14=-4+5/8c

Solution for -5/4c-14=-4+5/8c equation:

-5/4c-14=-4+5/8c

We move all terms to the left:

-5/4c-14-(-4+5/8c)=0


Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R



Domain of the equation: 8c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

-5/4c-(5/8c-4)-14=0

We get rid of parentheses

-5/4c-5/8c+4-14=0

We calculate fractions


(-40c)/32c^2+(-20c)/32c^2+4-14=0

We add all the numbers together, and all the variables

(-40c)/32c^2+(-20c)/32c^2-10=0

We multiply all the terms by the denominator


(-40c)+(-20c)-10*32c^2=0

Wy multiply elements

-320c^2+(-40c)+(-20c)=0

We get rid of parentheses

-320c^2-40c-20c=0

We add all the numbers together, and all the variables

-320c^2-60c=0

a = -320; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·(-320)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*-320}=\frac{0}{-640}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*-320}=\frac{120}{-640}
=-3/16
$