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-5/6e-2/3e=2
We move all terms to the left:
-5/6e-2/3e-(2)=0
Domain of the equation: 6e!=0
e!=0/6
e!=0
e∈R
Domain of the equation: 3e!=0We calculate fractions
e!=0/3
e!=0
e∈R
(-15e)/18e^2+(-12e)/18e^2-2=0
We multiply all the terms by the denominator
(-15e)+(-12e)-2*18e^2=0
Wy multiply elements
-36e^2+(-15e)+(-12e)=0
We get rid of parentheses
-36e^2-15e-12e=0
We add all the numbers together, and all the variables
-36e^2-27e=0
a = -36; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·(-36)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*-36}=\frac{0}{-72} =0 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*-36}=\frac{54}{-72} =-3/4 $
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