-5/w-2=-5/2w-4-4

Solution for -5/w-2=-5/2w-4-4 equation:

-5/w-2=-5/2w-4-4

We move all terms to the left:

-5/w-2-(-5/2w-4-4)=0


Domain of the equation: w!=0

w∈R



Domain of the equation: 2w-4-4)!=0

We move all terms containing w to the left, all other terms to the right

2w-4)!=4

w∈R


We add all the numbers together, and all the variables

-5/w-(-5/2w-8)-2=0

We get rid of parentheses

-5/w+5/2w+8-2=0

We calculate fractions


(-10w)/2w^2+5w/2w^2+8-2=0

We add all the numbers together, and all the variables

(-10w)/2w^2+5w/2w^2+6=0

We multiply all the terms by the denominator


(-10w)+5w+6*2w^2=0

We add all the numbers together, and all the variables

5w+(-10w)+6*2w^2=0

Wy multiply elements

12w^2+5w+(-10w)=0

We get rid of parentheses

12w^2+5w-10w=0

We add all the numbers together, and all the variables

12w^2-5w=0

a = 12; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·12·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*12}=\frac{0}{24}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*12}=\frac{10}{24}
=5/12
$