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-5/x=3/3x+7
We move all terms to the left:
-5/x-(3/3x+7)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x+7)!=0We get rid of parentheses
x∈R
-5/x-3/3x-7=0
We calculate fractions
(-15x)/3x^2+(-3x)/3x^2-7=0
We multiply all the terms by the denominator
(-15x)+(-3x)-7*3x^2=0
Wy multiply elements
-21x^2+(-15x)+(-3x)=0
We get rid of parentheses
-21x^2-15x-3x=0
We add all the numbers together, and all the variables
-21x^2-18x=0
a = -21; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·(-21)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*-21}=\frac{0}{-42} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*-21}=\frac{36}{-42} =-6/7 $
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