-50+12d=3(2d-4)+22

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Solution for -50+12d=3(2d-4)+22 equation: 



-50+12d=3(2d-4)+22

We move all terms to the left:

-50+12d-(3(2d-4)+22)=0



We calculate terms in parentheses: -(3(2d-4)+22), so:

3(2d-4)+22

We multiply parentheses

6d-12+22

We add all the numbers together, and all the variables

6d+10

Back to the equation:

-(6d+10)



We get rid of parentheses

12d-6d-10-50=0

We add all the numbers together, and all the variables

6d-60=0

We move all terms containing d to the left, all other terms to the right

6d=60

d=60/6

d=10

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