-50+7x+2=3(4x-4)-6

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Solution for -50+7x+2=3(4x-4)-6 equation: 



-50+7x+2=3(4x-4)-6

We move all terms to the left:

-50+7x+2-(3(4x-4)-6)=0

We add all the numbers together, and all the variables

7x-(3(4x-4)-6)-48=0



We calculate terms in parentheses: -(3(4x-4)-6), so:

3(4x-4)-6

We multiply parentheses

12x-12-6

We add all the numbers together, and all the variables

12x-18

Back to the equation:

-(12x-18)



We get rid of parentheses

7x-12x+18-48=0

We add all the numbers together, and all the variables

-5x-30=0

We move all terms containing x to the left, all other terms to the right

-5x=30

x=30/-5

x=-6

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