-50=4b-5(12+b)

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Solution for -50=4b-5(12+b) equation: 



-50=4b-5(12+b)

We move all terms to the left:

-50-(4b-5(12+b))=0

We add all the numbers together, and all the variables

-(4b-5(b+12))-50=0



We calculate terms in parentheses: -(4b-5(b+12)), so:

4b-5(b+12)

We multiply parentheses

4b-5b-60

We add all the numbers together, and all the variables

-1b-60

Back to the equation:

-(-1b-60)



We get rid of parentheses

1b+60-50=0

We add all the numbers together, and all the variables

b+10=0

We move all terms containing b to the left, all other terms to the right

b=-10

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