-50x2+10x=0

Solution for -50x2+10x=0 equation:

-50x^2+10x=0

a = -50; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-50)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-50}=\frac{-20}{-100}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-50}=\frac{0}{-100}
=0
$