-51+4y+5=2(4y-2)-6

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Solution for -51+4y+5=2(4y-2)-6 equation: 



-51+4y+5=2(4y-2)-6

We move all terms to the left:

-51+4y+5-(2(4y-2)-6)=0

We add all the numbers together, and all the variables

4y-(2(4y-2)-6)-46=0



We calculate terms in parentheses: -(2(4y-2)-6), so:

2(4y-2)-6

We multiply parentheses

8y-4-6

We add all the numbers together, and all the variables

8y-10

Back to the equation:

-(8y-10)



We get rid of parentheses

4y-8y+10-46=0

We add all the numbers together, and all the variables

-4y-36=0

We move all terms containing y to the left, all other terms to the right

-4y=36

y=36/-4

y=-9

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