-57+20y+3=6(4y-3)-8

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Solution for -57+20y+3=6(4y-3)-8 equation: 



-57+20y+3=6(4y-3)-8

We move all terms to the left:

-57+20y+3-(6(4y-3)-8)=0

We add all the numbers together, and all the variables

20y-(6(4y-3)-8)-54=0



We calculate terms in parentheses: -(6(4y-3)-8), so:

6(4y-3)-8

We multiply parentheses

24y-18-8

We add all the numbers together, and all the variables

24y-26

Back to the equation:

-(24y-26)



We get rid of parentheses

20y-24y+26-54=0

We add all the numbers together, and all the variables

-4y-28=0

We move all terms containing y to the left, all other terms to the right

-4y=28

y=28/-4

y=-7

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