-57-3(z-5)=4z-4(2-z)

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Solution for -57-3(z-5)=4z-4(2-z) equation:



-57-3(z-5)=4z-4(2-z)
We move all terms to the left:
-57-3(z-5)-(4z-4(2-z))=0
We add all the numbers together, and all the variables
-3(z-5)-(4z-4(-1z+2))-57=0
We multiply parentheses
-3z-(4z-4(-1z+2))+15-57=0
We calculate terms in parentheses: -(4z-4(-1z+2)), so:
4z-4(-1z+2)
We multiply parentheses
4z+4z-8
We add all the numbers together, and all the variables
8z-8
Back to the equation:
-(8z-8)
We add all the numbers together, and all the variables
-3z-(8z-8)-42=0
We get rid of parentheses
-3z-8z+8-42=0
We add all the numbers together, and all the variables
-11z-34=0
We move all terms containing z to the left, all other terms to the right
-11z=34
z=34/-11
z=-3+1/11

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