-5=(3-2b)+3b

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Solution for -5=(3-2b)+3b equation: 



-5=(3-2b)+3b

We move all terms to the left:

-5-((3-2b)+3b)=0

We add all the numbers together, and all the variables

-((-2b+3)+3b)-5=0



We calculate terms in parentheses: -((-2b+3)+3b), so:

(-2b+3)+3b

We add all the numbers together, and all the variables

3b+(-2b+3)

We get rid of parentheses

3b-2b+3

We add all the numbers together, and all the variables

b+3

Back to the equation:

-(b+3)



We get rid of parentheses

-b-3-5=0

We add all the numbers together, and all the variables

-1b-8=0

We move all terms containing b to the left, all other terms to the right

-b=8

b=8/-1

b=-8

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