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-5=1/2(2g-4)
We move all terms to the left:
-5-(1/2(2g-4))=0
Domain of the equation: 2(2g-4))!=0We multiply all the terms by the denominator
g∈R
-(1-5*2(2g-4))=0
We calculate terms in parentheses: -(1-5*2(2g-4)), so:We add all the numbers together, and all the variables
1-5*2(2g-4)
determiningTheFunctionDomain -5*2(2g-4)+1
Wy multiply elements
-10g(2+1
Back to the equation:
-(-10g(2+1)
-(-10g3=0
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