-5=2(10b-2)=31

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Solution for -5=2(10b-2)=31 equation: 



-5=2(10b-2)=31

We move all terms to the left:

-5-(2(10b-2))=0



We calculate terms in parentheses: -(2(10b-2)), so:

2(10b-2)

We multiply parentheses

20b-4

Back to the equation:

-(20b-4)



We get rid of parentheses

-20b+4-5=0

We add all the numbers together, and all the variables

-20b-1=0

We move all terms containing b to the left, all other terms to the right

-20b=1

b=1/-20

b=-1/20

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