-5=5/7(35-14x)+40

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Solution for -5=5/7(35-14x)+40 equation: 



-5=5/7(35-14x)+40

We move all terms to the left:

-5-(5/7(35-14x)+40)=0



Domain of the equation: 7(35-14x)+40)!=0

x∈R



We add all the numbers together, and all the variables

-(5/7(-14x+35)+40)-5=0

We multiply all the terms by the denominator


-(5-5*7(-14x+35)+40)=0



We calculate terms in parentheses: -(5-5*7(-14x+35)+40), so:

5-5*7(-14x+35)+40

determiningTheFunctionDomain
-5*7(-14x+35)+5+40

We add all the numbers together, and all the variables

-5*7(-14x+35)+45

Wy multiply elements

-35x(-+45

We use the square of the difference formula

-35x(-45

Back to the equation:

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