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-5=x2+3x+1
We move all terms to the left:
-5-(x2+3x+1)=0
We add all the numbers together, and all the variables
-(+x^2+3x+1)-5=0
We get rid of parentheses
-x^2-3x-1-5=0
We add all the numbers together, and all the variables
-1x^2-3x-6=0
a = -1; b = -3; c = -6;
Δ = b2-4ac
Δ = -32-4·(-1)·(-6)
Δ = -15
Delta is less than zero, so there is no solution for the equation
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