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-5a(a-1)=-5a-1a
We move all terms to the left:
-5a(a-1)-(-5a-1a)=0
We add all the numbers together, and all the variables
-5a(a-1)-(-6a)=0
We multiply parentheses
-5a^2+5a-(-6a)=0
We get rid of parentheses
-5a^2+5a+6a=0
We add all the numbers together, and all the variables
-5a^2+11a=0
a = -5; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-5)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-5}=\frac{-22}{-10} =2+1/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-5}=\frac{0}{-10} =0 $
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