-5b+24=8(b-6)6b

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Solution for -5b+24=8(b-6)6b equation:



-5b+24=8(b-6)6b
We move all terms to the left:
-5b+24-(8(b-6)6b)=0
We calculate terms in parentheses: -(8(b-6)6b), so:
8(b-6)6b
We multiply parentheses
48b^2-288b
Back to the equation:
-(48b^2-288b)
We get rid of parentheses
-48b^2-5b+288b+24=0
We add all the numbers together, and all the variables
-48b^2+283b+24=0
a = -48; b = 283; c = +24;
Δ = b2-4ac
Δ = 2832-4·(-48)·24
Δ = 84697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(283)-\sqrt{84697}}{2*-48}=\frac{-283-\sqrt{84697}}{-96} $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(283)+\sqrt{84697}}{2*-48}=\frac{-283+\sqrt{84697}}{-96} $

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