-5b+24=8(b-6)6b

Solution for -5b+24=8(b-6)6b equation:

-5b+24=8(b-6)6b

We move all terms to the left:

-5b+24-(8(b-6)6b)=0


We calculate terms in parentheses: -(8(b-6)6b), so:

8(b-6)6b

We multiply parentheses

48b^2-288b

Back to the equation:

-(48b^2-288b)


We get rid of parentheses

-48b^2-5b+288b+24=0

We add all the numbers together, and all the variables

-48b^2+283b+24=0

a = -48; b = 283; c = +24;
Δ = b2-4ac
Δ = 2832-4·(-48)·24
Δ = 84697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(283)-\sqrt{84697}}{2*-48}=\frac{-283-\sqrt{84697}}{-96}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(283)+\sqrt{84697}}{2*-48}=\frac{-283+\sqrt{84697}}{-96}
$