-5b+3(b+2)+4(b+1)=2

Solution for -5b+3(b+2)+4(b+1)=2 equation:

-5b+3(b+2)+4(b+1)=2

We simplify the equation to the form, which is simple to understand 
-5b+3(b+2)+4(b+1)=2

Reorder the terms in parentheses
-5b+(+3b+6)+4*(b+1)=2

Remove unnecessary parentheses
-5b+3b+6+4+*(+b+1+)=+2

Reorder the terms in parentheses
-5b+3b+6+(+4b+4)=2

Remove unnecessary parentheses
-5b+3b+6+4b+4=+2

We move all terms containing b to the left and all other terms to the right. 
-5b+3b+4b=+2-6-4

We simplify left and right side of the equation. 
+2b=-8

We divide both sides of the equation by 2 to get b. 
b=-4