-5m(m+6)+2(1+3m)=-2m-4m

Solution for -5m(m+6)+2(1+3m)=-2m-4m equation:

-5m(m+6)+2(1+3m)=-2m-4m

We move all terms to the left:

-5m(m+6)+2(1+3m)-(-2m-4m)=0

We add all the numbers together, and all the variables

-5m(m+6)+2(3m+1)-(-6m)=0

We multiply parentheses

-5m^2-30m+6m-(-6m)+2=0

We get rid of parentheses

-5m^2-30m+6m+6m+2=0

We add all the numbers together, and all the variables

-5m^2-18m+2=0

a = -5; b = -18; c = +2;
Δ = b2-4ac
Δ = -182-4·(-5)·2
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{91}}{2*-5}=\frac{18-2\sqrt{91}}{-10}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{91}}{2*-5}=\frac{18+2\sqrt{91}}{-10}
$