-5m+(3m-5)=2(m+15)

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Solution for -5m+(3m-5)=2(m+15) equation: 



-5m+(3m-5)=2(m+15)

We move all terms to the left:

-5m+(3m-5)-(2(m+15))=0

We get rid of parentheses

-5m+3m-(2(m+15))-5=0



We calculate terms in parentheses: -(2(m+15)), so:

2(m+15)

We multiply parentheses

2m+30

Back to the equation:

-(2m+30)



We add all the numbers together, and all the variables

-2m-(2m+30)-5=0

We get rid of parentheses

-2m-2m-30-5=0

We add all the numbers together, and all the variables

-4m-35=0

We move all terms containing m to the left, all other terms to the right

-4m=35

m=35/-4

m=-8+3/4

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