-5m2+28=-6m2-11m

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Solution for -5m2+28=-6m2-11m equation:



-5m^2+28=-6m^2-11m
We move all terms to the left:
-5m^2+28-(-6m^2-11m)=0
We get rid of parentheses
-5m^2+6m^2+11m+28=0
We add all the numbers together, and all the variables
m^2+11m+28=0
a = 1; b = 11; c = +28;
Δ = b2-4ac
Δ = 112-4·1·28
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3}{2*1}=\frac{-14}{2} =-7 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3}{2*1}=\frac{-8}{2} =-4 $

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