-5n+3n=4(n+2)-2(n-2)

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Solution for -5n+3n=4(n+2)-2(n-2) equation: 



-5n+3n=4(n+2)-2(n-2)

We move all terms to the left:

-5n+3n-(4(n+2)-2(n-2))=0

We add all the numbers together, and all the variables

-2n-(4(n+2)-2(n-2))=0



We calculate terms in parentheses: -(4(n+2)-2(n-2)), so:

4(n+2)-2(n-2)

We multiply parentheses

4n-2n+8+4

We add all the numbers together, and all the variables

2n+12

Back to the equation:

-(2n+12)



We get rid of parentheses

-2n-2n-12=0

We add all the numbers together, and all the variables

-4n-12=0

We move all terms containing n to the left, all other terms to the right

-4n=12

n=12/-4

n=-3

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