-5p-6(3-2p)=2(p-4)-20

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Solution for -5p-6(3-2p)=2(p-4)-20 equation: 



-5p-6(3-2p)=2(p-4)-20

We move all terms to the left:

-5p-6(3-2p)-(2(p-4)-20)=0

We add all the numbers together, and all the variables

-5p-6(-2p+3)-(2(p-4)-20)=0

We multiply parentheses

-5p+12p-(2(p-4)-20)-18=0



We calculate terms in parentheses: -(2(p-4)-20), so:

2(p-4)-20

We multiply parentheses

2p-8-20

We add all the numbers together, and all the variables

2p-28

Back to the equation:

-(2p-28)



We add all the numbers together, and all the variables

7p-(2p-28)-18=0

We get rid of parentheses

7p-2p+28-18=0

We add all the numbers together, and all the variables

5p+10=0

We move all terms containing p to the left, all other terms to the right

5p=-10

p=-10/5

p=-2

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