-5r-5(1+3r)=9(7-6r)

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Solution for -5r-5(1+3r)=9(7-6r) equation:



-5r-5(1+3r)=9(7-6r)
We move all terms to the left:
-5r-5(1+3r)-(9(7-6r))=0
We add all the numbers together, and all the variables
-5r-5(3r+1)-(9(-6r+7))=0
We multiply parentheses
-5r-15r-(9(-6r+7))-5=0
We calculate terms in parentheses: -(9(-6r+7)), so:
9(-6r+7)
We multiply parentheses
-54r+63
Back to the equation:
-(-54r+63)
We add all the numbers together, and all the variables
-20r-(-54r+63)-5=0
We get rid of parentheses
-20r+54r-63-5=0
We add all the numbers together, and all the variables
34r-68=0
We move all terms containing r to the left, all other terms to the right
34r=68
r=68/34
r=2

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