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-5t^2+10t+1=6
We move all terms to the left:
-5t^2+10t+1-(6)=0
We add all the numbers together, and all the variables
-5t^2+10t-5=0
a = -5; b = 10; c = -5;
Δ = b2-4ac
Δ = 102-4·(-5)·(-5)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{-10}{-10}=1$
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