-5t2+10t+1=6

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Solution for -5t2+10t+1=6 equation: 



-5t^2+10t+1=6

We move all terms to the left:

-5t^2+10t+1-(6)=0

We add all the numbers together, and all the variables

-5t^2+10t-5=0

a = -5; b = 10; c = -5;
Δ = b2-4ac
Δ = 102-4·(-5)·(-5)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-10}{-10}=1$

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