-5u(-4u+4)-4u=2(u-9)-9

Solution for -5u(-4u+4)-4u=2(u-9)-9 equation:

-5u(-4u+4)-4u=2(u-9)-9

We move all terms to the left:

-5u(-4u+4)-4u-(2(u-9)-9)=0

We add all the numbers together, and all the variables

-4u-5u(-4u+4)-(2(u-9)-9)=0

We multiply parentheses

20u^2-4u-20u-(2(u-9)-9)=0


We calculate terms in parentheses: -(2(u-9)-9), so:

2(u-9)-9

We multiply parentheses

2u-18-9

We add all the numbers together, and all the variables

2u-27

Back to the equation:

-(2u-27)


We add all the numbers together, and all the variables

20u^2-24u-(2u-27)=0

We get rid of parentheses

20u^2-24u-2u+27=0

We add all the numbers together, and all the variables

20u^2-26u+27=0

a = 20; b = -26; c = +27;
Δ = b2-4ac
Δ = -262-4·20·27
Δ = -1484
Delta is less than zero, so there is no solution for the equation