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-5u^2+13u-8=0
a = -5; b = 13; c = -8;
Δ = b2-4ac
Δ = 132-4·(-5)·(-8)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3}{2*-5}=\frac{-16}{-10} =1+3/5 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3}{2*-5}=\frac{-10}{-10} =1 $
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