-5v-40=-5-3(1+3v)

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Solution for -5v-40=-5-3(1+3v) equation: 



-5v-40=-5-3(1+3v)

We move all terms to the left:

-5v-40-(-5-3(1+3v))=0

We add all the numbers together, and all the variables

-5v-(-5-3(3v+1))-40=0



We calculate terms in parentheses: -(-5-3(3v+1)), so:

-5-3(3v+1)

determiningTheFunctionDomain
-3(3v+1)-5

We multiply parentheses

-9v-3-5

We add all the numbers together, and all the variables

-9v-8

Back to the equation:

-(-9v-8)



We get rid of parentheses

-5v+9v+8-40=0

We add all the numbers together, and all the variables

4v-32=0

We move all terms containing v to the left, all other terms to the right

4v=32

v=32/4

v=8

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