-5w(w+3)=w-6+6(2w+1)

Solution for -5w(w+3)=w-6+6(2w+1) equation:

-5w(w+3)=w-6+6(2w+1)

We move all terms to the left:

-5w(w+3)-(w-6+6(2w+1))=0

We multiply parentheses

-5w^2-15w-(w-6+6(2w+1))=0


We calculate terms in parentheses: -(w-6+6(2w+1)), so:

w-6+6(2w+1)

determiningTheFunctionDomain
w+6(2w+1)-6

We multiply parentheses

w+12w+6-6

We add all the numbers together, and all the variables

13w

Back to the equation:

-(13w)


We add all the numbers together, and all the variables

-5w^2-28w=0

a = -5; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·(-5)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*-5}=\frac{0}{-10}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*-5}=\frac{56}{-10}
=-5+3/5
$