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-5w(w-8)2=0
We multiply parentheses
-10w^2+80w=0
a = -10; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·(-10)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*-10}=\frac{-160}{-20} =+8 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*-10}=\frac{0}{-20} =0 $
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