-5w-10=2-(w+2)+1

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Solution for -5w-10=2-(w+2)+1 equation: 



-5w-10=2-(w+2)+1

We move all terms to the left:

-5w-10-(2-(w+2)+1)=0



We calculate terms in parentheses: -(2-(w+2)+1), so:

2-(w+2)+1

determiningTheFunctionDomain
-(w+2)+2+1

We add all the numbers together, and all the variables

-(w+2)+3

We get rid of parentheses

-w-2+3

We add all the numbers together, and all the variables

-1w+1

Back to the equation:

-(-1w+1)



We get rid of parentheses

-5w+1w-1-10=0

We add all the numbers together, and all the variables

-4w-11=0

We move all terms containing w to the left, all other terms to the right

-4w=11

w=11/-4

w=-2+3/4

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