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-5x(-3x-3)=14
We move all terms to the left:
-5x(-3x-3)-(14)=0
We multiply parentheses
15x^2+15x-14=0
a = 15; b = 15; c = -14;
Δ = b2-4ac
Δ = 152-4·15·(-14)
Δ = 1065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{1065}}{2*15}=\frac{-15-\sqrt{1065}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{1065}}{2*15}=\frac{-15+\sqrt{1065}}{30} $
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