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-5x(-5x+12)+6x=95
We move all terms to the left:
-5x(-5x+12)+6x-(95)=0
We add all the numbers together, and all the variables
6x-5x(-5x+12)-95=0
We multiply parentheses
25x^2+6x-60x-95=0
We add all the numbers together, and all the variables
25x^2-54x-95=0
a = 25; b = -54; c = -95;
Δ = b2-4ac
Δ = -542-4·25·(-95)
Δ = 12416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12416}=\sqrt{64*194}=\sqrt{64}*\sqrt{194}=8\sqrt{194}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-8\sqrt{194}}{2*25}=\frac{54-8\sqrt{194}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+8\sqrt{194}}{2*25}=\frac{54+8\sqrt{194}}{50} $
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