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-5x(-7-4)x=-2(3x-4)
We move all terms to the left:
-5x(-7-4)x-(-2(3x-4))=0
We add all the numbers together, and all the variables
-5x(-11)x-(-2(3x-4))=0
We multiply parentheses
55x^2-(-2(3x-4))=0
We calculate terms in parentheses: -(-2(3x-4)), so:We get rid of parentheses
-2(3x-4)
We multiply parentheses
-6x+8
Back to the equation:
-(-6x+8)
55x^2+6x-8=0
a = 55; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·55·(-8)
Δ = 1796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1796}=\sqrt{4*449}=\sqrt{4}*\sqrt{449}=2\sqrt{449}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{449}}{2*55}=\frac{-6-2\sqrt{449}}{110} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{449}}{2*55}=\frac{-6+2\sqrt{449}}{110} $
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