-5x(-7-4x)=2(3x-4)

Solution for -5x(-7-4x)=2(3x-4) equation:

-5x(-7-4x)=2(3x-4)

We move all terms to the left:

-5x(-7-4x)-(2(3x-4))=0

We add all the numbers together, and all the variables

-5x(-4x-7)-(2(3x-4))=0

We multiply parentheses

20x^2+35x-(2(3x-4))=0


We calculate terms in parentheses: -(2(3x-4)), so:

2(3x-4)

We multiply parentheses

6x-8

Back to the equation:

-(6x-8)


We get rid of parentheses

20x^2+35x-6x+8=0

We add all the numbers together, and all the variables

20x^2+29x+8=0

a = 20; b = 29; c = +8;
Δ = b2-4ac
Δ = 292-4·20·8
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{201}}{2*20}=\frac{-29-\sqrt{201}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{201}}{2*20}=\frac{-29+\sqrt{201}}{40}
$