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-5x(2)=-50
We move all terms to the left:
-5x(2)-(-50)=0
We add all the numbers together, and all the variables
-5x^2+50=0
a = -5; b = 0; c = +50;
Δ = b2-4ac
Δ = 02-4·(-5)·50
Δ = 1000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1000}=\sqrt{100*10}=\sqrt{100}*\sqrt{10}=10\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{10}}{2*-5}=\frac{0-10\sqrt{10}}{-10} =-\frac{10\sqrt{10}}{-10} =-\frac{\sqrt{10}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{10}}{2*-5}=\frac{0+10\sqrt{10}}{-10} =\frac{10\sqrt{10}}{-10} =\frac{\sqrt{10}}{-1} $
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