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-5x(3x+4)+2=0
We multiply parentheses
-15x^2-20x+2=0
a = -15; b = -20; c = +2;
Δ = b2-4ac
Δ = -202-4·(-15)·2
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{130}}{2*-15}=\frac{20-2\sqrt{130}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{130}}{2*-15}=\frac{20+2\sqrt{130}}{-30} $
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