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-5x(3x-3)=2x+3(x+4)
We move all terms to the left:
-5x(3x-3)-(2x+3(x+4))=0
We multiply parentheses
-15x^2+15x-(2x+3(x+4))=0
We calculate terms in parentheses: -(2x+3(x+4)), so:We get rid of parentheses
2x+3(x+4)
We multiply parentheses
2x+3x+12
We add all the numbers together, and all the variables
5x+12
Back to the equation:
-(5x+12)
-15x^2+15x-5x-12=0
We add all the numbers together, and all the variables
-15x^2+10x-12=0
a = -15; b = 10; c = -12;
Δ = b2-4ac
Δ = 102-4·(-15)·(-12)
Δ = -620
Delta is less than zero, so there is no solution for the equation
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