-5x(7x-5)+7=-35x+32

Solution for -5x(7x-5)+7=-35x+32 equation:

-5x(7x-5)+7=-35x+32

We move all terms to the left:

-5x(7x-5)+7-(-35x+32)=0

We multiply parentheses

-35x^2+25x-(-35x+32)+7=0

We get rid of parentheses

-35x^2+25x+35x-32+7=0

We add all the numbers together, and all the variables

-35x^2+60x-25=0

a = -35; b = 60; c = -25;
Δ = b2-4ac
Δ = 602-4·(-35)·(-25)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-10}{2*-35}=\frac{-70}{-70}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+10}{2*-35}=\frac{-50}{-70}
=5/7
$