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-5x(x-10)=6(x-10)
We move all terms to the left:
-5x(x-10)-(6(x-10))=0
We multiply parentheses
-5x^2+50x-(6(x-10))=0
We calculate terms in parentheses: -(6(x-10)), so:We get rid of parentheses
6(x-10)
We multiply parentheses
6x-60
Back to the equation:
-(6x-60)
-5x^2+50x-6x+60=0
We add all the numbers together, and all the variables
-5x^2+44x+60=0
a = -5; b = 44; c = +60;
Δ = b2-4ac
Δ = 442-4·(-5)·60
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-56}{2*-5}=\frac{-100}{-10} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+56}{2*-5}=\frac{12}{-10} =-1+1/5 $
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