-5x(x-5)+4x+4=35

Solution for -5x(x-5)+4x+4=35 equation:

-5x(x-5)+4x+4=35

We move all terms to the left:

-5x(x-5)+4x+4-(35)=0

We add all the numbers together, and all the variables

4x-5x(x-5)-31=0

We multiply parentheses

-5x^2+4x+25x-31=0

We add all the numbers together, and all the variables

-5x^2+29x-31=0

a = -5; b = 29; c = -31;
Δ = b2-4ac
Δ = 292-4·(-5)·(-31)
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{221}}{2*-5}=\frac{-29-\sqrt{221}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{221}}{2*-5}=\frac{-29+\sqrt{221}}{-10}
$