-5x+3-2(x-4)=4(x+3)-1

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Solution for -5x+3-2(x-4)=4(x+3)-1 equation: 



-5x+3-2(x-4)=4(x+3)-1

We move all terms to the left:

-5x+3-2(x-4)-(4(x+3)-1)=0

We multiply parentheses

-5x-2x-(4(x+3)-1)+8+3=0



We calculate terms in parentheses: -(4(x+3)-1), so:

4(x+3)-1

We multiply parentheses

4x+12-1

We add all the numbers together, and all the variables

4x+11

Back to the equation:

-(4x+11)



We add all the numbers together, and all the variables

-7x-(4x+11)+11=0

We get rid of parentheses

-7x-4x-11+11=0

We add all the numbers together, and all the variables

-11x=0

x=0/-11

x=0

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