-5x-(-7x-4x)=-2x(3x+4)

Solution for -5x-(-7x-4x)=-2x(3x+4) equation:

-5x-(-7x-4x)=-2x(3x+4)

We move all terms to the left:

-5x-(-7x-4x)-(-2x(3x+4))=0

We add all the numbers together, and all the variables

-5x-(-11x)-(-2x(3x+4))=0

We get rid of parentheses

-5x+11x-(-2x(3x+4))=0


We calculate terms in parentheses: -(-2x(3x+4)), so:

-2x(3x+4)

We multiply parentheses

-6x^2-8x

Back to the equation:

-(-6x^2-8x)


We add all the numbers together, and all the variables

-(-6x^2-8x)+6x=0

We get rid of parentheses

6x^2+8x+6x=0

We add all the numbers together, and all the variables

6x^2+14x=0

a = 6; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·6·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*6}=\frac{-28}{12}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*6}=\frac{0}{12}
=0
$